Determine the cop of a refrigerator
WebQuestion: Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5140 kJ/h for each kW of power it consumes. Also, determine the rate of heat rejection to the outside air. (Round the final answers to two decimal places and the nearest whole number, respectively.) The COP is .................. . WebApr 13, 2024 · Regarding the average temperature of the refrigerator compartments, very adequate thermal conditions were observed; thus, the alternative refrigerants showed very similar conditions to R134a. For the coefficient of performance (COP) and considering R134a as a reference, it was observed that R513A presented the greatest reduction of …
Determine the cop of a refrigerator
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WebExpert Answer. Refrigerant-134a enters the evaporator coils placed at the back of the freezer section of a household refrigerator at 100 kPa with a quality of 20 percent and leaves at 100 kPa and-26°C. If the compressor … WebDisregarding any heat transfer and pressure drops in the connecting lines between the components, Refrigerant-134a enters the compressor of a refrigerator as superheated vapor at 0.14 MPa and -10°C at a rate of 0.05 kg/s and leaves at 0.8 MPa and 50°C. The refrigerant is cooled in the condenser to 26°C and 0.72 MPa and is throttled to 0.15 MPa.
WebSep 9, 2024 · Thus, for a heat pump, the appropriate definition of the coefficient of performance is the heating effect (i.e. Q2) divided by the … WebQuestion. A household refrigerator that has a power input of 450 W and a COP of 1.5 is to cool 5 large watermelons, 10 kg each, to 8 ^\circ {} ∘ C. If the watermelons are initially at 28 ^\circ {} ∘ C, determine how long it will take for the refrigerator to cool them. The watermelons can be treated as water whose specific heat is 4.2 kJ/kgK.
Web2296, Page 4 International Refrigeration and Air Conditioning Conference at Purdue, July 12-15, 2010 where ûp cab=K ffm ff 2=K fzm fz 2 is the pressure drop in both the frozen- and fresh-food compartments (see Fig. 3), and ûp fan is the pressure head provided by the fan, which was correlated as follows (Waltrich, 2008), Δ = 3 i 0 i p fan e i m fan (13) The … WebThe coefficient of performance (COP) of reversible or irreversible refrigerator or heat pump is given by. COP R = 1/ ( (Q H /Q L )-1) COP HP = 1/ (1- (Q L /Q H )) where. Q H = the amount of heat rejected to the. high-temperature reservoir. Q L = the amount of heat received from the. low-temperature reservoir.
WebMechanical Engineering questions and answers. Determine the COP of a refrigerator that removes heat from the food compartment at a rate of 5080 kJ/h for each kW of power it consumes. Also, determine the rate of heat rejection to the outside air. The COP of the refrigerator is The rate of heat rejection to the outside air is kJ/h. d <.
http://www.learningaboutelectronics.com/Articles/Coefficient-of-performance-calculator.php in base 10 crossword clueWebA household refrigerator runs one-fourth of the time and removes heat from the food compartment at an average rate of 800 kJ/n. If the COP of the refrigerator is 2.3, determine the power the refrigerator draws when running. 300 Wh COP Refrigerator The power the refrigerator draws when running is KW inbuilt methods in pythonWebSince the ratio of heat removed to work input is defined as the COP of a refrigerator, this corresponds to a COP of 1.8. ... Using this equation with COP = 1.8 and T 0 = 25°C, we determine T = −81.3°C. This is the temperature a heat reservoir would have if a Carnot refrigerator with a COP of 1.8 operated between this reservoir and another ... in barkley square songWebFeb 15, 2024 · Here’s the equation to calculate COP: COP (heating) = Q (hot)/W =Q (cold) +W/ W For ideal heat pumps that have no irreversibility’s and losses, the equation can be: COP (heating) = T (hot) / T (hot) – T (cold) Different Types Of Heat Pumps Explained Geothermal Heat Pumps inbuilt micWebME354 Thermodynamics 2 Quiz #3 - T02: Name: ID #: Problem: A commercial refrigerator with refrigerant- 134a as the working fluidisusedtokeepthe refrigerated space at −30 C by rejecting its waste heat to cooling water that enters the condenser at 18 C at a rate of 0.25kg/sand leaves at 26 C.The refrigerant enters the condenser at 1.2MPa and … in base 2 what number comes after 1101WebThe coefficient of performance (COP) is a measure of efficiency of the refrigerator. The COP of a domestic refrigerator is the ratio of the refrigeration capacity to the energy supplied to the compressor. It can be expressed by equation 3 (Dossat, 1978; Dincer, 2003). P Q in COP 2 1 1 4 m h h m h h (3) inbuilt methods of arrays in javaWeb1. A Carnot heat engine operates between a heat source at 1300 K and the environment at 300 K.The net work produced by the engine is used to power a Carnot refrigerator which removes heat, from a cooled space at − 2 2 ∘ C at a rate of 370 kJ / min and rejects it to the same environment at 300 K.Determine a) the entropy changes of the heat sources in the … inbuilt microphone in laptop not working